0=((x^2)-2x)/(4x-8)

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Solution for 0=((x^2)-2x)/(4x-8) equation: 


D( x )

4*x-8 = 0

4*x-8 = 0

4*x-8 = 0

4*x-8 = 0 // + 8

4*x = 8 // : 4

x = 8/4

x = 2

x in (-oo:2) U (2:+oo)

0 = (x^2-(2*x))/(4*x-8) // - (x^2-(2*x))/(4*x-8)

0-((x^2-(2*x))/(4*x-8)) = 0

-((x^2-2*x)/(4*x-8)) = 0

(-1*(x^2-2*x))/(4*x-8) = 0

x^2-2*x = 0

x*(x-2) = 0

x-2 = 0 // + 2

x = 2

x*(x-2) = 0

(-1*x*(x-2))/(4*x-8) = 0

( -1 )

-1 = 0

x belongs to the empty set

( x-2 )

x-2 = 0 // + 2

x = 2

( x )

x = 0

x in { 2} 

x = 0

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